posted by Hannah on .
A reaction has a rate law, rate = k times A times B squared. What is the overall order of the reaction.
I think that the order is 0. Is this correct?
Sorry I had to post the question using the word times but for some reason this site would not let me post the original equation using the brackets.
Jiskha doesn't allow students to post web addresses. But you don't need a web address to show this. You want rate = k[A][B]2.
The reaction is 1st order in A (because the exponent of A is 1, 2nd order in B (because the exponent of B is 2, and 3rd order over all (because the sum of 1 + 2= 3).
oh I understand you have to add them. Thank you.