Posted by Jessi on Sunday, February 19, 2012 at 2:32pm.
dy/dx= 6(x^2+x-1)^2 (2x+1)
at (-1,-2)
dy/dx= 6(1-1-1)^2 (-2+1)
= -6
so now you have the slope of -6 and a point(-1,-2)
continue ....
So
y2-y1=m(x2-x1)
y-(-2)=-6(x-(-1)
y=6x-1
therefore the slope of tangent is 6?
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