Posted by
Jessi on
.
Determine the slope of the tangent to the curve y=2(x^2+x1)^3 at (1, 2)

Calculus 
Reiny,
dy/dx= 6(x^2+x1)^2 (2x+1)
at (1,2)
dy/dx= 6(111)^2 (2+1)
= 6
so now you have the slope of 6 and a point(1,2)
continue ....

Calculus 
Jessi,
So
y2y1=m(x2x1)
y(2)=6(x(1)
y=6x1
therefore the slope of tangent is 6?