Posted by **Jessi** on Sunday, February 19, 2012 at 2:32pm.

Determine the slope of the tangent to the curve y=2(x^2+x-1)^3 at (-1, -2)

- Calculus -
**Reiny**, Sunday, February 19, 2012 at 2:37pm
dy/dx= 6(x^2+x-1)^2 (2x+1)

at (-1,-2)

dy/dx= 6(1-1-1)^2 (-2+1)

= -6

so now you have the slope of -6 and a point(-1,-2)

continue ....

- Calculus -
**Jessi**, Sunday, February 19, 2012 at 2:54pm
So

y2-y1=m(x2-x1)

y-(-2)=-6(x-(-1)

y=6x-1

therefore the slope of tangent is 6?

## Answer this Question

## Related Questions

- 12th Grade Calculus - 1. a.) Find an equation for the line perpendicular to the ...
- Calculus - There are two neighboring points P and Q on the curve f(x)=x^2 (a) ...
- calculus - 1. Given the curve a. Find an expression for the slope of the curve ...
- Calculus - Determine the slope of the tangent line to the curve y=2x^3-3x^2+1 at...
- Calc AB - Suppose that f(x) is an invertible function (that is, has an inverse ...
- calculus - Find the equation of the tangent line to the curve y=sqrt(x) at x = c...
- calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
- Calculus - Consider the curve given by y^2 = 2+xy (a) show that dy/dx= y/(2y-x...
- math - Find the slope of the secant to the curve f(x) = -2logx + 3 between: (1 ...
- Calculus - Could someone please help me with this question; Find the tangent to ...