a hot air balloon is hovering at an altitude of 6000 meters. The pilot decides that it is time to descend and turns off the balloon's burners.Once the balloon reaches the ground, the gas inside the balloon occupies 980 m cubed and is at atmospheric pressure. If the pressure of the gas inside of the balloon was 75,000 Pascals at its highest altitude, what was the volume of the gas at that time. i did 75,000*980/6000 and got 12250 msqr/pa. can you tell me if that is right or am i missing something.

To calculate the volume of the gas inside the balloon at its highest altitude, you need to use the gas law equation, which states:

P1*V1 = P2*V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

In this case, the initial pressure of the gas inside the balloon was 75,000 Pascals, and the final pressure is atmospheric pressure (which is approximately 98,000 Pascals at sea level). The final volume is given as 980 m^3.

Using the gas law equation, we can rearrange it to solve for V1:

V1 = (P2*V2) / P1

Substituting the values:

V1 = (98,000 * 980) / 75,000

Calculating this, we get:

V1 ≈ 1,274.67 m^3

So, the volume of the gas inside the balloon at its highest altitude was approximately 1,274.67 m^3. This means that the value you obtained, 12,250 m^2/Pa, is incorrect.