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July 30, 2014

July 30, 2014

Posted by **Seth** on Sunday, February 19, 2012 at 8:26am.

- math -
**Reiny**, Sunday, February 19, 2012 at 10:06amso we are solving ......

200( 1.025)^(t) = 200(1.03)^(t-2) , where t is number of half-years

1.025^(t) = 1.03^(t-2)

log both sides

log (1.025^(t)) = log(1.03^(t-2))

t log 1.025 = (t-2) log 1.03

t log 1.025 = t log 1.03 - 2log 1.03

t log 1.025 - t log 1.03 = -2log 1.03

t(log 1.025 - log 1.03) = -2log 1.03

t = -2log 1.03/(log 1.025 - log 1.03)

t = 12.1486 half years after jan 1, 2000

I will leave it to you to figure out the month and year

Remember t is in half years,

so it will take 6 years and .1486(6) months .....

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