Homework Help: math

Posted by jhay on Sunday, February 19, 2012 at 3:37am.

1.) Find the solution set of
2sin squared θ-1= 0 if 180 degrees is less than or equal to θ is less than or equal to 360 degrees

2.) prove:

2cotθ/cot squared θ -1 = sin2 θ sec2 θ

math - Reiny, Sunday, February 19, 2012 at 8:31am
2 sin^2 Ų = 1
sin^2 Ų = 1/2
sin Ų = 1/√2
if 180 ≤ Ų ≤ 360°
then Ų = 225° or 315°

2.

Did you mean:
2cotŲ/(cot^2 Ų - 1) = sin^2 Ų sec^2 Ų ?
If so, then it is not and identity, (I tried it with Ų=20°)
did you mean:
2cotŲ/cot^2 Ų - 1 = sin^2 Ų sec^2 Ų ?
If so, then it is not and identity, (I tried it with Ų=20°)

did you mean:
2cotŲ/cot^2 Ų - 1 = sin 2Ų sec 2Ų ?
If so, then it is not and identity, (I tried it with Ų=20°)

etc.
math - micheal, Thursday, February 21, 2013 at 6:17am
4^(x 1) - 6^x - 2.9^(x 1) = 0

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