Posted by **jhay** on Sunday, February 19, 2012 at 3:37am.

1.) Find the solution set of

2sin squared θ-1= 0 if 180 degrees is less than or equal to θ is less than or equal to 360 degrees

2.) prove:

2cotθ/cot squared θ -1 = sin2 θ sec2 θ

- math -
**Reiny**, Sunday, February 19, 2012 at 8:31am
2 sin^2 Ø = 1

sin^2 Ø = 1/2

sin Ø = 1/√2

if 180 ≤ Ø ≤ 360°

then Ø = 225° or 315°

2.

Did you mean:

2cotØ/(cot^2 Ø - 1) = sin^2 Ø sec^2 Ø ?

If so, then it is not and identity, (I tried it with Ø=20°)

did you mean:

2cotØ/cot^2 Ø - 1 = sin^2 Ø sec^2 Ø ?

If so, then it is not and identity, (I tried it with Ø=20°)

did you mean:

2cotØ/cot^2 Ø - 1 = sin 2Ø sec 2Ø ?

If so, then it is not and identity, (I tried it with Ø=20°)

etc.

- math -
**micheal**, Thursday, February 21, 2013 at 6:17am
4^(x 1) - 6^x - 2.9^(x 1) = 0

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