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March 27, 2017

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1.) Find the solution set of
2sin squared θ-1= 0 if 180 degrees is less than or equal to θ is less than or equal to 360 degrees

2.) prove:

2cotθ/cot squared θ -1 = sin2 θ sec2 θ

  • math - ,

    2 sin^2 Ø = 1
    sin^2 Ø = 1/2
    sin Ø = 1/√2
    if 180 ≤ Ø ≤ 360°
    then Ø = 225° or 315°

    2.

    Did you mean:
    2cotØ/(cot^2 Ø - 1) = sin^2 Ø sec^2 Ø ?
    If so, then it is not and identity, (I tried it with Ø=20°)
    did you mean:
    2cotØ/cot^2 Ø - 1 = sin^2 Ø sec^2 Ø ?
    If so, then it is not and identity, (I tried it with Ø=20°)

    did you mean:
    2cotØ/cot^2 Ø - 1 = sin 2Ø sec 2Ø ?
    If so, then it is not and identity, (I tried it with Ø=20°)

    etc.

  • math - ,

    4^(x 1) - 6^x - 2.9^(x 1) = 0

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