Posted by carlton on Sunday, February 19, 2012 at 1:25am.
find the derivative
ln [x^3 +((x+3)^3)((x^2)+4)^7
- cal 2 - drwls, Sunday, February 19, 2012 at 1:30am
You left out a ] somewhere
- cal 2 - Steve, Sunday, February 19, 2012 at 11:39am
Hmm the logical fix would be
ln [x^3 +((x+3)^3)]((x^2)+4)^7
a^3 + b^3 = (a+b)(a^2-ab+b^2), so
x^3 + (x+3)^3 = (x+(x+3))(x^2 - x(x+3) + (x+3)^2)
= (2x+3)(x^2 + 3x + 9)
and the log of the product then becomes
y = ln(2x+3) + ln(x^2+3x+9) + 7ln(x^2+4)
y' = 2/(2x+3) + (2x+3)/(x^2+3x+9) + 14x/(x^2+4)
If my placement of  is wrong, please feel free to clarify
- cal 2 - Geminese, Wednesday, March 7, 2012 at 2:59pm
Find the derivative of the function
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