February 19, 2017

Homework Help: Chem

Posted by Jen on Saturday, February 18, 2012 at 10:34pm.

A solution is made by dissolving 0.584 mol of nonelectrolyte solute in 883 g of benzene. Calculate the freezing point and boiling point of the solution.

I got Tf as 3.39 degrees Celsius
I got Tb as 1.67 degrees Celsius

It marked me wrong and said "You have given the change in the freezing and boiling points. Identify the normal freezing and boiling points of benzene, then add or subtract the change."

Can you please explain and let me know the correct answers so I don't miss it again. Thanks.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions