Posted by **tee** on Saturday, February 18, 2012 at 10:05pm.

the international space station orbits 350 km above earth's surface. earth's radius is about 6370 km.use the pythagorean theorem to find the distance from the space station to earth's horizon.

- math -
**drwls**, Saturday, February 18, 2012 at 10:37pm
sqrt[(6370+350)^2 -(6370)^2]

= 2140 km

The hypotenuse is 6720 and the radius (6370) from the center to the point of tangency is perpendicular to the earth's surface

- math -
**Reiny**, Saturday, February 18, 2012 at 10:37pm
let that distance be x

solve ...

x^2 + 6370^2 = 6720^2

( I got 2140.44)

- math -
**Kiamora**, Thursday, November 3, 2016 at 2:47pm
Yeah so add 20 plus 11 and get 47 , that's the short way , because once you do that , you'll easily get 2140.5 , you welcome.

## Answer This Question

## Related Questions

- geometry - The Hubble Space Telescope is orbiting Earth 600 km above Earth's ...
- Physics - When out in space in International Space Station (ISS), Astronauts ...
- physics - A 2130-kg space station orbits Earth at an altitude of 455 km. Find ...
- Physics, Please Help - A 2130-kg space station orbits Earth at an altitude of ...
- Geometry - 11-1 Lines that Intersect Circles 8. The International Space Station ...
- Astronomy 1010 - The International Space Station orbits approximately 350 km ...
- Astronomy 1010 - The International Space Station orbits approximately 350 km ...
- Physics: Astronauts and space - When out in space in International Space Station...
- Physics - When out in space in International Space Station (ISS), Astronauts ...
- geometry - The radius of the earth is approximately 6371 km.If the international...

More Related Questions