I just need to know the net ionic equation and balance them. I figured the equation. but the net and balance is harder.

Co(NO3)2 (aq) + NaOH (aq) = CoOH (s) + Na(NO3)2 (aq)

Co(NO3)2 (aq) + Na2CO3 (aq) = CoCO3 (s) + Na2(NO3)2 (aq)

Co(NO3)2 (aq) + Na3PO4 (aq) = CoPO4 (s) + Na3(NO3)2 (aq)

To find the net ionic equation and balance the equations you have provided, we will go step-by-step.

1. Co(NO3)2(aq) + NaOH(aq) → CoOH(s) + Na(NO3)2(aq)

To balance the equation, we need an equal number of atoms on both sides. Let's start with the Co atoms:

On the left side, we have one Co atom, and on the right side, we have one Co atom in CoOH. So the Co is already balanced.

Next, let's balance the NO3 ions:

On the left side, we have two NO3 ions from Co(NO3)2, and on the right side, we also have two NO3 ions from Na(NO3)2. So the NO3 ions are already balanced.

Next, let's balance the Na atoms:

On the left side, we have one Na atom from NaOH, and on the right side, we have one Na atom from Na(NO3)2. So the Na atoms are already balanced.

Therefore, the net ionic equation for this reaction is:

Co(NO3)2(aq) + 2NaOH(aq) → CoOH(s) + 2NaNO3(aq)

2. Co(NO3)2(aq) + Na2CO3(aq) → CoCO3(s) + Na2(NO3)2(aq)

To balance this equation, we again start with the Co atoms:

On the left side, we have one Co atom, and on the right side, we have one Co atom in CoCO3. So the Co is already balanced.

Next, let's balance the NO3 ions:

On the left side, we have two NO3 ions from Co(NO3)2, and on the right side, we also have two NO3 ions from Na2(NO3)2. So the NO3 ions are already balanced.

Next, let's balance the Na atoms:

On the left side, we have two Na atoms from Na2CO3, and on the right side, we have two Na atoms from Na2(NO3)2. So the Na atoms are already balanced.

Therefore, the net ionic equation for this reaction is:

Co(NO3)2(aq) + Na2CO3(aq) → CoCO3(s) + 2NaNO3(aq)

3. Co(NO3)2(aq) + Na3PO4(aq) → CoPO4(s) + Na3(NO3)2(aq)

To balance this equation, we start with the Co atoms:

On the left side, we have one Co atom, and on the right side, we have one Co atom in CoPO4. So the Co is already balanced.

Next, let's balance the NO3 ions:

On the left side, we have two NO3 ions from Co(NO3)2, and on the right side, we also have two NO3 ions from Na3(NO3)2. So the NO3 ions are already balanced.

Next, let's balance the Na atoms:

On the left side, we have three Na atoms from Na3PO4, and on the right side, we have three Na atoms from Na3(NO3)2. So the Na atoms are already balanced.

Therefore, the net ionic equation for this reaction is:

Co(NO3)2(aq) + 3Na3PO4(aq) → CoPO4(s) + 3NaNO3(aq)

To write the net ionic equation and balance the given chemical equations, we first need to write the complete ionic equations. Then, we can identify the spectator ions and cancel them to obtain the net ionic equation. Let's go step by step:

1. Co(NO3)2 (aq) + 2NaOH (aq) → Co(OH)2 (s) + 2NaNO3 (aq)

To balance the equation:

Co(NO3)2 (aq) + 2NaOH (aq) → Co(OH)2 (s) + 2NaNO3 (aq)

2. Co(NO3)2 (aq) + Na2CO3 (aq) → CoCO3 (s) + 2NaNO3 (aq)

To balance the equation:

Co(NO3)2 (aq) + Na2CO3 (aq) → CoCO3 (s) + 2NaNO3 (aq)

3. 3Co(NO3)2 (aq) + 2Na3PO4 (aq) → Co3(PO4)2 (s) + 6NaNO3 (aq)

To balance the equation:

3Co(NO3)2 (aq) + 2Na3PO4 (aq) → Co3(PO4)2 (s) + 6NaNO3 (aq)

Now, let's write the net ionic equations for each of these reactions:

1. Net Ionic Equation: Co2+ (aq) + 2OH- (aq) → Co(OH)2 (s)

2. Net Ionic Equation: Co2+ (aq) + CO32- (aq) → CoCO3 (s)

3. Net Ionic Equation: 3Co2+ (aq) + 2PO43- (aq) → Co3(PO4)2 (s)

These are the net ionic equations for the given reactions.

Na2CO3 ( ) + Co(NO3)2 ( ) --> 2NaNO3 ( ) + CoCO3 ( ) complete ionic equation And net ionic equation