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December 19, 2014

December 19, 2014

Posted by **Desperate!!!!** on Saturday, February 18, 2012 at 1:42pm.

- Calculus -
**john**, Saturday, February 18, 2012 at 4:34pmv(t)=s'(t)=150-32t

set s(t)=200 find out when the rock is 200 feet above the ground.

200=150t-16t^2

t=(5/16)+or-(15-sqrt(97))

0=150t-16t^2

t=75/8 not 0 because it started on the ground

the velocity when it strikes the ground is v(75/8)=-150

the other velocity is v((5/16)+or-(15-sqrt(97)))=304.387 or -24.836

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