A book slides off a table top with a speed of 11 meters per second . It strikes the floor in 0.66 seconds . How tall was the table ( in meters)?
h = Vo*t + 0.5g*t^2,
h = 0 + 4.9*(066)^2 = 2.13 m.
y-yo=yo*t+1/2(9.8)(O.66)2
=O + 4.9(O.66)2
=2.13m
To find the height of the table, we can use the equation of motion for a falling object:
s = ut + (1/2)at^2
where:
s = height of the table (unknown)
u = initial velocity (11 m/s, sliding off speed)
t = time taken to hit the floor (0.66 s)
a = acceleration due to gravity (approximated as 9.8 m/s^2)
Rearranging the equation, we have:
s = ut + (1/2)at^2
s = (11 m/s)(0.66 s) + (1/2)(9.8 m/s^2)(0.66 s)^2
s = 7.26 m + 3.0498 m
s ≈ 10.3098 m
Therefore, the height of the table is approximately 10.31 meters.