Posted by **Jack** on Saturday, February 18, 2012 at 12:19pm.

2^(3x+1)=2^)2/x) I don't know what to do here to get both of the xs

- Algebra 2 -
**MathGuru**, Sunday, February 19, 2012 at 7:55pm
Since you have the same base, do this:

3x + 1 = 2/x

Now we can solve for x:

x(3x + 1) = x(2/x) -->multiplying both sides by x to get rid of x in the denominator. (Whatever operation you do to one side of an equation you must do to the other side as well.)

3x^2 + x = 2

Set the equation equal to 0:

3x^2 + x - 2 = 0

Try to factor:

(3x - 2)(x + 1)

Set each factor equal to 0 and solve for x:

3x - 2 = 0; x = 2/3

x + 1 = 0; x = -1

You have two possible solutions. Check these with the original equation. It always helps to check your work!

I hope this helps.

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