Posted by **Jack** on Saturday, February 18, 2012 at 12:19pm.

2^(3x+1)=2^)2/x) I don't know what to do here to get both of the xs

- Algebra 2 -
**MathGuru**, Sunday, February 19, 2012 at 7:55pm
Since you have the same base, do this:

3x + 1 = 2/x

Now we can solve for x:

x(3x + 1) = x(2/x) -->multiplying both sides by x to get rid of x in the denominator. (Whatever operation you do to one side of an equation you must do to the other side as well.)

3x^2 + x = 2

Set the equation equal to 0:

3x^2 + x - 2 = 0

Try to factor:

(3x - 2)(x + 1)

Set each factor equal to 0 and solve for x:

3x - 2 = 0; x = 2/3

x + 1 = 0; x = -1

You have two possible solutions. Check these with the original equation. It always helps to check your work!

I hope this helps.

## Answer this Question

## Related Questions

- Pre Algebra - Here is another one I need help with. -5x+20=-60 ( remember it is ...
- Algebra 2 - 2^(3x+1)=2^)2/x) I don't know what to do here to get both of the xs
- Algebra - 89. Solve for x in the equation: 6/7x - 6 = -2 I posted this before, ...
- Algebra - Here is what I got to do : write an inequality for my classmates to ...
- algebra - how do I do this Solve for x. 3x – 2y = 6 Add 2y to both sides and ...
- Algebra - 2(0.5-3y) + y > (4y-0.2)8 I understand how to solve the problem, ...
- algebra - im not to good at algebra so here goes im supposed to multiply 5.(3.2...
- College Algebra - okay so using y = (-5/6)x + 3 how do i find the corresponding ...
- Algebra - Solve Q= (N-S)/ N for N So when I multiply both sides by N I get Q(N...
- Algebra--Correction? - Solve the absolute value equation. I I will represent ...

More Related Questions