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October 21, 2014

October 21, 2014

Posted by **bety** on Saturday, February 18, 2012 at 9:59am.

If its tires have diameter 24.0 and are rolling without sliding or slipping, what is their angular velocity?

- Physics?? -
**drwls**, Saturday, February 18, 2012 at 10:26amYou must provide dimensions along with your numbers. 62 what? mph? 24.0 what? inches?

A nonslipping tire's speed (and that of the car) is

V = R*w

where w is the angular velocity in radians per second.

You do the numbers.

The length and speed dimensions must be consistent. (feet and feet/s or meters and meters/s)

- Physics?? -
**bety**, Saturday, February 18, 2012 at 10:35amits 62 mi/h and 24.0in

- Physics?? -
**bety**, Saturday, February 18, 2012 at 10:49amdo i do 2pi/ 62 first?

- Physics?? -
**drwls**, Saturday, February 18, 2012 at 10:55amw = V/R

V = 62 mi/h = 90.93 ft/s

R = 24 in = 0.6667 ft

Now that you have consistent dimensions for V and R,

w = 90.93/0.6667 = 136.4 rad/s

- Physics?? -
**bety**, Saturday, February 18, 2012 at 11:07ami got the anwser wrong

- Physics?? -
**drwls**, Saturday, February 18, 2012 at 1:42pmIt looks right to me. Sometimes the online problem writers get it wrong, and sometimes it's me. The equation is correct.

- Physics?? -
**Nonso**, Saturday, February 18, 2012 at 6:47pmBut cant u jus convert the diameter to meter nd d v to m/s. Besides that 24inc was the diameter which should hav been divided by two to get the radius

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