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Posted by on Saturday, February 18, 2012 at 2:50am.

1.25 mol of NOCl was placed in a 2.50 L reaction chamber at 427 celciciu degre . After equilibrium was reached, 1.1 mole of NOCl remained. Calculate the equilibrium constant Kc for the reaction

  • Chemistry chemical equilibrium - , Saturday, February 18, 2012 at 4:16pm

    ............2NOCl ==> 2NO + Cl2
    initial.....1.25.......0.....0
    change.......-2x.......2x....x
    equil......1.25-2x.....2x.....x

    From problem, 1.25-2x =1.1 mols
    Therefore, x = 0.075 mols
    Convert x, 2x, and 1.25 to moles/L. M = moles/2.5L.
    You now know (NO), (Cl2), and (NOCl).
    Substitute into the Kc expression for NOCl and solve for Kc.

  • Chemistry chemical equilibrium - , Friday, April 26, 2013 at 4:34am

    0.000432

  • Chemistry chemical equilibrium - , Sunday, January 12, 2014 at 7:03am

    where did you get this question from ?

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