posted by Mary on .
An electron and a proton are each placed at
rest in an electric ﬁeld of 363 N/C.
What is the velocity of the electron 76.1 ns
after being released? Consider the direction
parallel to the ﬁeld to be positive. The elementary charge is 1.60218 × 10
C and the
mass of an electron is 9.10939 × 10
The acceleration of the electron is
a = e*E/m = 6.38*10^13 m/s^2
After time t, the speed is (1/2) a t^2.
In your case, t = 76.1*10^-9 s