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Acetic acid is a polar molecule and can form hydrogen bonds with water molecules. Therefore, it has high solubility in water. Yet acetic acid is also soluble in benzene (C6H6), a nonpolar solvent that lacks the ability to form hydrogen bonds. A solution of 3.8g of CH3COOH in 80g of C6H6 has a freezing point of 3.5 degrees celsius. Calculate the molar mass of the solute and suggest what it's structure might be.

  • Chemistry - ,

    Look up the freezing point of benzene, then delta T = f.p.=3.5 = Kf*m
    Solve for molality.

    molality = moles/kg solvent
    Solve for moles.

    moles acetic acid = grams acetic acid/molar mass acetic acid
    Solve for molar mass. You would expect to find 60 for the molar mass CH3COOH.

    You will also need to look up the Kf for benzene.

  • Chemistry - ,


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