A baseball is thrown horizontally from a height of 12.00 m above the ground with a speed of 25.5 m/s. Where is the ball after 0.80 s have elapsed?
The ball is a horizontal distance of m from the launch point.
To find the horizontal distance the ball has traveled after 0.80 s, we need to use the horizontal velocity and time.
Given:
Initial height (h) = 12.00 m
Initial speed (v) = 25.5 m/s
Time (t) = 0.80 s
Since the ball is thrown horizontally, there is no vertical acceleration. Thus, the horizontal velocity remains constant throughout the motion.
To find the horizontal distance (d), we can use the formula:
d = v * t
where:
d = horizontal distance
v = velocity
t = time
Plugging in the values we have:
d = 25.5 m/s * 0.80 s
Calculating this:
d = 20.40 m
Therefore, the ball is a horizontal distance of 20.40 m from the launch point after 0.80 s have elapsed.