NaCl+H2SO4
Write the balanced net ionic equation.
To write the balanced net ionic equation for the reaction between Sodium Chloride (NaCl) and Sulfuric Acid (H2SO4), we first need to determine the products formed.
When NaCl reacts with H2SO4, it forms Sodium Sulfate (Na2SO4) and Hydrochloric Acid (HCl).
The balanced molecular equation is:
2 NaCl + H2SO4 -> Na2SO4 + 2 HCl
Now, let's write the net ionic equation by separating the ions that are aqueous and canceling out the spectator ions:
NaCl(aq) + H2SO4(aq) -> Na2SO4(aq) + HCl(aq)
The net ionic equation is:
Na+(aq) + Cl-(aq) + H+(aq) + SO4^2-(aq) -> Na+(aq) + SO4^2-(aq) + H+(aq) + Cl-(aq)
Simplifying, the net ionic equation is:
Cl-(aq) + H+(aq) -> HCl(aq)
To write the balanced net ionic equation for the reaction between NaCl and H2SO4, you first need to write the balanced molecular equation. The balanced molecular equation is:
NaCl + H2SO4 → Na2SO4 + HCl
Next, you need to determine the states of matter for each of the substances involved in the reaction. Sodium chloride (NaCl) and sodium sulfate (Na2SO4) are both soluble in water, so they are both aqueous (aq). Hydrochloric acid (HCl) is also soluble in water, so it is aqueous (aq) as well. However, sulfuric acid (H2SO4) is a strong acid and completely ionizes in water, so it dissociates into its ions, resulting in hydrogen ions (H+) and sulfate ions (SO4^2-). Therefore, H2SO4 is written as H+ (aq) and SO4^2- (aq).
Now, you can write the balanced net ionic equation by eliminating the spectator ions, which are the ions that appear on both sides of the equation without undergoing a change. In this case, sodium ions (Na+) and sulfate ions (SO4^2-) are spectator ions, so they will be eliminated:
H+ (aq) + Cl- (aq) → HCl (aq)
The balanced net ionic equation for the reaction between NaCl and H2SO4 is H+ (aq) + Cl- (aq) → HCl (aq).
2NaCl(s) + H2SO4(l) ==> Na2SO4(aq) + 2HCl(g)
2Cl^- + 2H^+ ==> 2HCl