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April 2, 2015

April 2, 2015

Posted by **Reza** on Friday, February 17, 2012 at 4:19pm.

g(x) = x^7 − 7x^5

Honestly, I have no idea how to find the critical number!

- Math -
**Reiny**, Friday, February 17, 2012 at 4:44pmby critical numbers, they mean

the turning points, (maximim and minimum points)

any points of inflection

the x and the y -intercepts

so for y-intercept, let x = 0

so g(0) = 0, the origin (0,0) is both an x and a y intercept.

for more x-intercepts , let y = 0

x^7 - 7x^5 = 0

x^5(x^2 - 7) = 0

so x = 0 , x = ± √7

g'(x) = 7x^6 - 35x^4 = 0 for max/mins

7x^4(x^2 - 5) = 0

x = 0 or x = ± √5

g''(x) = 42x^5 - 140x^3

= 0 for any points of inflection

14x^3(3x^2 - 10) = 0

x = 0 or x = ± √(10/3)

since (0,0) is both a turning point and a point of inflection, It is neither a maximim nor a minimum

so you have 4 other different x values to sub back into the original equation to find the corresponding y value of the points,

I will leave that up to you

- Math -
**Reza**, Friday, February 17, 2012 at 7:32pmThank you I really appreciate your help :)

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