Luis has a coin that is weighted so that the probability that Heads appears when it is tossed is 0.55. Suppose that the coin is tossed 3 times. What is the probability that all 3 tosses are Heads?

please help ,e to solve this question .
i dont'know if i +am right
.55/2+.55/2+.55/2= 1.65/2 =0.82 Answer
Am i right ?

no, the prob of three heads with that coin

= (.55)(.55)(.55) = appr .166

why are you dividing by 2 ???
Didn't your answer seem illogical to you?

To solve this question, we need to use the concept of probability and the multiplication rule for independent events.

The probability of getting a Heads (H) on a single toss is given as 0.55.

When tossing the coin multiple times, we can assume that each toss is independent of the others. Therefore, we can use the multiplication rule to find the probability of all three tosses being Heads.

The multiplication rule states that the probability of two independent events occurring together is the product of their individual probabilities.

So, the probability of all three tosses being Heads can be calculated as:

0.55 * 0.55 * 0.55 = 0.166375

Therefore, the probability that all three tosses are Heads is approximately 0.166375.

Your calculation of adding the probabilities is incorrect. When events are independent, we multiply the probabilities, not add them.

So, the correct answer is approximately 0.166375, not 0.82.

To find the probability that all 3 tosses are heads, you need to multiply the probabilities of each individual toss being heads.

In this case, the probability of heads appearing on each toss is given as 0.55.

Therefore, the probability of all 3 tosses being heads is:
0.55 * 0.55 * 0.55 = 0.166375

So, the probability that all 3 tosses are heads is approximately 0.166 or 16.6%.