Posted by Peter on Friday, February 17, 2012 at 1:03am.
You have 20 grams of phosphorus32 that decays 5% per day. How long will it take for hlaf of the original amount to decay?

Algebra 2 Decay  DrBob222, Friday, February 17, 2012 at 1:32am
This may not be the math process you want. From a chemists standpoint, I would do the following.
ln(No/N) = kt. We must determine k.
So at zero time we start with 20 g. At the end of 1 day we have 20g5% = 19 g. Plug that into the first order equation of ln(20/19) = k(1 day)
k = 0.0513
Then ln(20/10) = 0.0513(t)
Solve for t. If I didn't goof that is
13.51 days which I would round to 13.5 days.

Algebra 2 Decay  Reiny, Friday, February 17, 2012 at 7:56am
Using the "continuous" decay formula, I got
.5 = 1(e^(.05t) )
ln .5  .05t lne, but ln e = 1
t = .05/ln .5 = .072134.. years
= 26.3 days

Algebra 2 Decay  DrBob222, Friday, February 17, 2012 at 11:37am
I looked up the half life of P32. It is 14.28 days. I suspect 5% decay in the problem is just a close number.
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