Posted by Angelina on Thursday, February 16, 2012 at 11:58pm.
I was thinking that it would be .90tan(70)=2.47 m/s^2 but I am wrong so I don't know how to do this...
Let the rope tension be T.
T sin70 = M V^2/R
T cos70 = M g
Now, divide the first equation by the second one.
tan70 = V^2/(R*g)
V^2 = (0.90)(9.8)(2.747)= 24.23 m^2/s^2
V = 4.92 m/s
Your answer does not have the dimensions of velocity, and must depend upon g.
What is the tangential speed of the ball?
thnks but i tried both 24.23m^2/s^2 and 4.92 n neither are right i dont understand whats wrong
Related Questions
physics - A 0.700-kg ball is on the end of a rope that is 2.20 m in length. The ...
physics - A 0.700-kg ball is on the end of a rope that is 2.20 m in length. The ...
physics - A 0.700-kg ball is on the end of a rope that is 2.20 m in length. The...
Physics to drwls question to answer given earlier - A 0.700-kg ball is on the ...
physics - An athlete swings a 4.30 kg ball horizontally on the end of a rope. ...
physics - In preparation for a demonstration on conservation of energy, a ...
Physics - An athlete swings a 3.46 kg ball horizontally on the end of a rope. ...
physics - In preparation for a demonstration on conservation of energy, a ...
physics - A bowling ball weighing 71.8 N is attached to the ceiling by a rope of...
physics - An athlete swings a 3.06 kg ball horizontally on the end of a rope. ...
For Further Reading