Posted by **Angelina** on Thursday, February 16, 2012 at 11:58pm.

A 0.700-kg ball is on the end of a rope that is 0.90 m in length. The ball and rope are attached to a pole and the entire apparatus, including the pole, rotates about the pole's symmetry axis. The rope makes an angle of 70.0° with respect to the vertical as shown. What is the tangential speed of the ball?

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**Angelina**, Friday, February 17, 2012 at 12:00am
I was thinking that it would be .90tan(70)=2.47 m/s^2 but I am wrong so I don't know how to do this...

- physics -
**drwls**, Friday, February 17, 2012 at 2:28am
Let the rope tension be T.

T sin70 = M V^2/R

T cos70 = M g

Now, divide the first equation by the second one.

tan70 = V^2/(R*g)

V^2 = (0.90)(9.8)(2.747)= 24.23 m^2/s^2

V = 4.92 m/s

Your answer does not have the dimensions of velocity, and must depend upon g.

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**Angelina**, Friday, February 17, 2012 at 4:34pm
What is the tangential speed of the ball?

thnks but i tried both 24.23m^2/s^2 and 4.92 n neither are right i dont understand whats wrong

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**Jim**, Tuesday, March 11, 2014 at 9:48pm
Radius should be 0.90Sin(70) that would account for the length of the path that the stone is traveling in. Use the equation above and substitute .90Sin(70) for the radius.

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