Posted by Kate on Thursday, February 16, 2012 at 11:07pm.
0.045 mols = 45 millimoles which I like better; it keeps all those zeros out of the way.
45 mmoles Br^- x 1/3 = mmoles AlBr3 since there are 3 Br^-/molecule AlBr3. That's 15 mmoles in the 15 mL.
That was the aliquot from 23 mL; therefore 15 mmoles x 23/15 was mmoles in the 23 mL sample. 15 x 23/15 = 23 mmoles (you don't even need a calculator so far).
So we had 23 mmoles in the original 11 mL. M = mmoles/mL = 23/11 = 2.09M
Kate, I think I worked a problem for you earlier that looked a lot like this. If so I must have not read it carefully, for I don't think I approached it this way. If so be sure and check that answer versus this problem.
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