Posted by tori on .
On a map, Town A is 8 km due south of Town B, Town C is 9 km from Town A, and Town C is 3 km from Town B (see figure below). Find the bearing from Town A to Town C and the bearing from Town B to Town C.

geometry 
yoyoma,
Hello, there is no figure but I shall try my best to figure it out.
I think this is probably a triangle.
B
 C
 /
 /
A
AB= 8
AC=9
BC=3
A is 9 km SW of C and B is 3 km NW of C. I hope this helps. 
geometry 
tori,
Thank you a ton!!

geometry 
yoyoma,
No problem!

geometry 
Steve,
To find the actual bearings, find the angles A,B,C, using the law of cosines. For example,
BC^{2} = AB^{2} + AC^{2}  2*AB*AC*cosA
9 = 64 + 81  144cosA
cosA = 136/144
A = 19º