solve for x:
-3x^2+6x-3=0
divide by -3
x^2-2x+1=0
(x-1)(x-1)=0
x=1
factor it
(-3x+3)(x-1)=0
x=1 OR x=1
x=1double root
thanks guys!
To solve the quadratic equation -3x^2 + 6x - 3 = 0 for x, you can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
Here, a = -3, b = 6, and c = -3.
Substituting these values into the quadratic formula, we have:
x = (-6 ± √(6^2 - 4(-3)(-3))) / (2(-3))
x = (-6 ± √(36 - 36)) / (-6)
x = (-6 ± √0) / (-6)
As the discriminant (the term inside the square root) is zero, the solutions will be real and equal.
x = -6 / -6
x = 1
Therefore, the value of x that satisfies the equation -3x^2 + 6x - 3 = 0 is x = 1.