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Calculate the pH of a solution made by adding 3.50 g of lithium oxide (Li2O) to enough water to make 1.290 L of solution. (Kw = 1.0 10-14)


    ..........Li2O + HOH ==> 2LiOH
    1 mol Li2O produces 2 mols LiOH. How many moles Li2O do you have? I see mol = grams/molar mass
    mol Li2O = 3.50 g Li2O/molar mass Li2O = ?
    Then twice that gives moles LiOH produced.
    M = mols LiOH/L LiOH.
    M LiOH = moles OH^-; convert to H^+ by
    H^+)(OH^-) = Kw ; then convert to pH.
    pH = -log(H^+)

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