Homework Help: physics

Posted by Adam on Thursday, February 16, 2012 at 4:36pm.

You want to push a 66-kg box up a 30° ramp. The coefficient of kinetic friction between the ramp and the box is 0.35. With what magnitude force parallel to the ramp should you push on the box so that it moves up the ramp at a constant speed?
N

physics - Henry, Saturday, February 18, 2012 at 10:23am
Wb = mg = 66kg * 9.8N/kg = 647 N. =
Wt. of box.

Fb = 647 N. @ 30 Deg. = Force of box.
Fp = 647*sin30 = 323.5 N. = Force parallel to ramp.
Fv = 647*cos30 = 560.3 N. = Force perpendicular to ramp.

Fk = u * Fv = 0.35 * 560.3 = 196.1 N. =
Force of kinetic friction.

Fn = Fap - Fp - Fk = 0, a = 0.
Fap - 323.5 - 196.1 = 0,
Fap - 519.6 = 0,
Fap = 519.6 N. = Force applied.

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