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April 18, 2014

April 18, 2014

Posted by **Johnathan** on Thursday, February 16, 2012 at 11:33am.

- Calculus -
**MathMate**, Thursday, February 16, 2012 at 2:54pmHint:

1. Use implicit differentiation to find y'.

2. Equate y' to -1 and solve for all possible values of x and y.

I find x=1,y=1 lies on the curve where the tangent is -1.

Check my work.

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