Wednesday

July 23, 2014

July 23, 2014

Posted by **Johnathan** on Thursday, February 16, 2012 at 11:33am.

- Calculus -
**MathMate**, Thursday, February 16, 2012 at 2:54pmHint:

1. Use implicit differentiation to find y'.

2. Equate y' to -1 and solve for all possible values of x and y.

I find x=1,y=1 lies on the curve where the tangent is -1.

Check my work.

**Related Questions**

Calculus - The line that is normal to the curve x^2=2xy-3y^2=0 at(1,1) ...

calculus - Find all points on the curve x^2y^2+xy=2 where the slope of tangent ...

Calculus - Find all points on the curve x^2y^2+2xy=3 where the slope of the ...

calculus - 1. Given the curve a. Find an expression for the slope of the curve ...

calculus - dy/dx= (2x-2xy)/(x^2+2y) find all points on the curve where x=2. show...

calculus - dy/dx= (2x-2xy)/(x^2+2y) Find all points on the curve where x=2. Show...

calculus - dy/dx= (2x-2xy)/(x^2+2y) Find all points on the curve where x=2. Show...

12th Grade Calculus - 1. a.) Find an equation for the line perpendicular to the ...

calculus - The equation x^2 y+2xy^3=8defines y as a function of x,y=f(x), near x...

Calculus - the curve: (x)(y^2)-(x^3)(y)=6 (dy/dx)=(3(x^2)y-(y^2))/(2xy-(x^3)) a...