a ball is dropped from a height of 10 meters.if the energy of the ball is reduced by 40% after striking the ground,how high can the ball bounce back?

It can bounce to 40% of the original height, or 4 meters in this case.

If the energy is reduced by 40%, then 60% is left. Therefore, PE = mgH = KE (at hitting the ground). Upward motion

0.6KE=0.6mgH = mgh. Then h=0.6x10=6 m.

Yes, I misread the question. 60% of the original height is correct

Mgh=k.e so the p. e=100x the 40% energy is reduced so we subtract the 40%of 100x=60xso height =60x/10=6m

To find out how high the ball can bounce back, we need to determine the percentage of energy it retains after hitting the ground. Here's how you can calculate it:

1. Start by understanding that the initial height of the ball is 10 meters, and it falls to the ground due to gravity.
2. When the ball hits the ground, it loses a certain percentage of its energy. In this case, it loses 40% of its energy.
3. To calculate the remaining energy after hitting the ground, subtract 40% from 100%: 100% - 40% = 60%.
4. The ball will then use this remaining energy to bounce back up.
5. According to the conservation of energy, the potential energy it regains after bouncing back will be equal to the energy it had before hitting the ground, which is 60% of the initial energy.
6. Multiply the remaining energy (60%) by the initial height (10 meters) to find the maximum height it can bounce back: 60% × 10 meters = 6 meters.

Therefore, the ball can bounce back to a height of 6 meters.