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April 20, 2014

April 20, 2014

Posted by **chrystabelle** on Thursday, February 16, 2012 at 5:19am.

- maths -
**Reiny**, Thursday, February 16, 2012 at 8:34amlet

(x-1)/((x+1)(x-2)^2) = A/(x-1) + B/(x-2) + C/(x-2)^2

multiply both sides by (x+1)(x-2)^2

A(x-2)^2 + B(x-2)(x+1) + C(x+1) = x-1

let x = 2, ---> 3C = 1 or C=13

let x = -1 ---> 9A + -2 or A = -2/9

let x = 0 ----> 4A - 2B + C = -1

4(-2/9) - 2B + 1/3 = -1

times 9

-8 - 18B + 3 = -9

B = 2/9

so (x-1)/(x-2)^2 = -2/(9(x+1)) + 2/(9(x-2)) + 1/(3(x-2)^2)

verified with Wolfram:

http://www.wolframalpha.com/input/?i=%28x-1%29%2F%28%28x%2B1%29%28x-2%29%5E2%29

- typo - maths -
**Reiny**, Thursday, February 16, 2012 at 8:36amin the middle of the solution above the line should read:

et x = 2, ---> 3C = 1 or C=1/3

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