February 24, 2017

Homework Help: physics

Posted by Daniel on Thursday, February 16, 2012 at 1:27am.

A proton moves in a constant electric field from point A to point B. The magnitude of the electric field is 6.4 × 10^4 N/C; and it is directed as shown in the drawing, the direction opposite to the motion of the proton. If the distance from point A to point B is 0.50 m, what is the change in the proton's electric potential energy, EPEB – EPEA?

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