Posted by Kelly on Wednesday, February 15, 2012 at 10:22pm.
Do you replace each card after your select it? If so, P = (13/52)^8 = ?
If not, P = 13/52 * 12/51 * 11/50 * 10/49 * 9/48 * 8/47 * 7/46 * 6/45 = ?
Do you think you could find a rule for the second probability?
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