Friday

October 31, 2014

October 31, 2014

Posted by **Candy** on Wednesday, February 15, 2012 at 9:07pm.

I really need help please.

- PLEASE PLEASE HELP!!!! -
**Candy**, Wednesday, February 15, 2012 at 9:50pmI'm almost getting ready 2 go 2 sleep and i really really need help. Just show me how to set the problem up and I can just solve it from there. Thanks :)

- Algebra-Trig Please Help ASAP -
**Steve**, Thursday, February 16, 2012 at 11:27amIf the balloon is between the stones, then: Let the balloon be x away from the first stone, and 1-x away from the other

h/x = tan 15° = .268

h/(1-x) = tan 17° = .306

.268x = .306(1-x)

x = .533

1-x = .467

height = .1428 mi = 754 ft

If the balloon is not between the stones, let it be x from the farther stone and x-1 from the nearer

h/x = tan 15° = .268

h/(x-1) = tan 17° = .306

.268x = .306(x-1)

x = 4.5

x-1 = 3.5

h = .268*4.5 = 1.206 mi = 6367 ft

**Answer this Question**

**Related Questions**

Pre-Calc - A hot-air balloon is floating above a straight road. To estimate ...

math - a captive balloon is connected to a ground station A by a cable of length...

trigonometry - a captive balloon is connected to a ground station A by a cable ...

trigonometry - a captive balloon is connected to a ground station A by a cable ...

trig - howard and keight who are 2km apart are on a horizontal plane observe a ...

Trigonometry - Two observers who are 2 miles apart on a horizontal plane observe...

pre-calc - two observers 3 miles apart and facing each other find that the ...

trig - weather balloon is directly west of two observing stations that are 10 mi...

trigonometry - howard and keight who are 2km apart are on a horizontal plane ...

algebra - A weather balloon is directly west of two observing stations that are ...