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November 26, 2014

November 26, 2014

Posted by **Candy** on Wednesday, February 15, 2012 at 9:07pm.

I really need help please.

- PLEASE PLEASE HELP!!!! -
**Candy**, Wednesday, February 15, 2012 at 9:50pmI'm almost getting ready 2 go 2 sleep and i really really need help. Just show me how to set the problem up and I can just solve it from there. Thanks :)

- Algebra-Trig Please Help ASAP -
**Steve**, Thursday, February 16, 2012 at 11:27amIf the balloon is between the stones, then: Let the balloon be x away from the first stone, and 1-x away from the other

h/x = tan 15° = .268

h/(1-x) = tan 17° = .306

.268x = .306(1-x)

x = .533

1-x = .467

height = .1428 mi = 754 ft

If the balloon is not between the stones, let it be x from the farther stone and x-1 from the nearer

h/x = tan 15° = .268

h/(x-1) = tan 17° = .306

.268x = .306(x-1)

x = 4.5

x-1 = 3.5

h = .268*4.5 = 1.206 mi = 6367 ft

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