Posted by Candy on Wednesday, February 15, 2012 at 9:07pm.
I'm almost getting ready 2 go 2 sleep and i really really need help. Just show me how to set the problem up and I can just solve it from there. Thanks :)
If the balloon is between the stones, then: Let the balloon be x away from the first stone, and 1-x away from the other
h/x = tan 15° = .268
h/(1-x) = tan 17° = .306
.268x = .306(1-x)
x = .533
1-x = .467
height = .1428 mi = 754 ft
If the balloon is not between the stones, let it be x from the farther stone and x-1 from the nearer
h/x = tan 15° = .268
h/(x-1) = tan 17° = .306
.268x = .306(x-1)
x = 4.5
x-1 = 3.5
h = .268*4.5 = 1.206 mi = 6367 ft
Related Questions
Pre-Calc - A hot-air balloon is floating above a straight road. To estimate ...
trig - howard and keight who are 2km apart are on a horizontal plane observe a ...
pre-calc - two observers 3 miles apart and facing each other find that the ...
trigonometry - howard and keight who are 2km apart are on a horizontal plane ...
trig - weather balloon is directly west of two observing stations that are 10 mi...
algebra - A weather balloon is directly west of two observing stations that are ...
Trig - From two different tracking stations, a weather balloon is spotted from ...
geometry - Two lines intersect to form two pairs of vertical angles.Angle 1 with...
geometry - 1. the opposite angles of a parallelogram measure(x=30) and (2x-50)....
algebra-trig help asap - Evaluate the expression. Assume that all angles are in ...
For Further Reading
