Posted by Arron on .
A concentration cell based on the following half reaction at 317 K
(Cu^2+) + (2e-) --> (Cu) SRP = 0.34 V
Has initial concentrations of 1.33 M Cu2+, 0.393 M Cu2+, and a potential of 0.01665 V at these conditions. After 4.1 hours the new potential of the cell is found to be 0.004008 V. What is the concentration of Cu2+ at the cathode at this new potential?