A model of s skyscraper is 1.6 in. long,2.8 in. wide, and 11.2in. high.The scale factor is 8 in. 250 ft. What is the actual dimension of the skyscraper.
height=11.2in (250ft/8in)
wide:2.8in*(250ft/8in)
and so on.
1 1 and 1
2000 ft2
To find the actual dimensions of the skyscraper, we need to use the given scale factor. The scale factor tells us how many units on the model represent one unit in real life.
Given:
Model dimensions:
Length = 1.6 in
Width = 2.8 in
Height = 11.2 in
Scale factor:
1 unit on the model = 8 in in real life
1 unit on the model = 250 ft in real life
To find the actual dimensions, we need to convert the dimensions of the model from inches to the real-life unit (feet).
Length of the skyscraper:
1 unit on the model = 8 in in real life
1.6 in on the model = (8 in/1 unit) * (1.6 in) = 12.8 in
1 ft = 12 in
Therefore, the length of the skyscraper is (12.8 in) / (12 in/1 ft) = 1.0667 ft
Width of the skyscraper:
1 unit on the model = 8 in in real life
2.8 in on the model = (8 in/1 unit) * (2.8 in) = 22.4 in
1 ft = 12 in
Therefore, the width of the skyscraper is (22.4 in) / (12 in/1 ft) = 1.8667 ft
Height of the skyscraper:
1 unit on the model = 250 ft in real life
11.2 in on the model = (250 ft/1 unit) * (11.2 in) = 2800 in
1 ft = 12 in
Therefore, the height of the skyscraper is (2800 in) / (12 in/1 ft) = 233.33 ft
Thus, the actual dimensions of the skyscraper are approximately:
Length = 1.0667 ft
Width = 1.8667 ft
Height = 233.33 ft