Evaluate the following expression:
d/dx (integration sign: upper=1 and lower= -3) (2t^3 + 3)dt =
I am given the following options:
2t^3 + 3
56
5
-28.0
None of the above
Would the result of the expression be 0 or 5???
It would be -28. For future notice, the integral is going from the interval -3 to 1(from point a to b)...this information will come in handy if you have to take physics
To evaluate the given expression, which involves differentiation and integration, we need to follow a step-by-step process:
Step 1: Differentiate the integrand with respect to "x."
The integration sign represents integration with respect to "t," so we need to apply the chain rule of differentiation here.
d/dx (integration sign: upper=1 and lower= -3) (2t^3 + 3)dt
= (d/dx) [(integration sign: upper=1 and lower= -3) (2t^3 + 3)dt]
Since the integrand is not dependent on "x," the derivative of the expression is 0.
Therefore, the result of the expression is 0.
None of the provided options (2t^3 + 3, 56, 5, -28.0, and None of the above) match the result of the expression, which is 0.