A 42kg person on a merry-go-round is traveling in a circle with a radius of 2m at a speed of 5 m/s. It asked for the acceleration which I got a 12.5 m/s (second square) and it also asked for the net horizontal force which I got at 525 N but I couldn't figure out how to get the final question which is this- (c) How does it compare with the person's weight?

Fhor.,net / W =

To compare the net horizontal force (Fhor.,net) with the person's weight (W), you need to calculate the ratio of the two.

First, let's calculate the person's weight. The weight of an object is given by the formula:

W = m * g

where W is the weight, m is the mass, and g is the acceleration due to gravity (approximately 9.8 m/s^2). In this case, since we know the mass is 42 kg, we can calculate the weight:

W = 42 kg * 9.8 m/s^2
W = 411.6 N

Next, let's calculate the ratio of the net horizontal force to the weight:

Fhor.,net/W = (Fhor.,net) / W

From your calculations, you found that the net horizontal force is 525 N. Plugging in the values:

Fhor.,net/W = 525 N / 411.6 N

Now, divide 525 N by 411.6 N to get the ratio:

Fhor.,net/W = 1.275

So, the ratio Fhor.,net/W is approximately 1.275. This means that the net horizontal force is 1.275 times greater than the person's weight.