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Posted by on Wednesday, February 15, 2012 at 5:20pm.

What would be the pH of a solution prepared by combining equal quantities of NaH2PO4 and Na2HPO4? Explain with an equation.

  • AP CHEMISTRY - , Wednesday, February 15, 2012 at 5:22pm

    It will be pKa2.
    pH = pKa2 + log[(base)/(acid)]
    If base = acid, then log 1 = 0 and pH = pKa2.

  • AP CHEMISTRY - , Wednesday, February 15, 2012 at 5:25pm

    How do u find pKa2

  • AP CHEMISTRY - , Wednesday, February 15, 2012 at 5:37pm

    Look up Ka2, (and Ka1 and Ka3 will be in the same table) for H3PO4.
    Then pKa2 = -log(Ka2) = ?

  • AP CHEMISTRY - , Wednesday, April 2, 2014 at 9:59pm

    ka2=6.2x10^-8
    pka2=-log(ka2)=-log(6.2x10^-8)=7.2
    pH=7.2

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