What would be the pH of a solution prepared by combining equal quantities of NaH2PO4 and Na2HPO4? Explain with an equation.
AP CHEMISTRY - DrBob222, Wednesday, February 15, 2012 at 5:22pm
It will be pKa2.
pH = pKa2 + log[(base)/(acid)]
If base = acid, then log 1 = 0 and pH = pKa2.
AP CHEMISTRY - ERAGON, Wednesday, February 15, 2012 at 5:25pm
How do u find pKa2
AP CHEMISTRY - DrBob222, Wednesday, February 15, 2012 at 5:37pm
Look up Ka2, (and Ka1 and Ka3 will be in the same table) for H3PO4.
Then pKa2 = -log(Ka2) = ?
AP CHEMISTRY - barca7, Wednesday, April 2, 2014 at 9:59pm