Monday

July 28, 2014

July 28, 2014

Posted by **Anonymous** on Wednesday, February 15, 2012 at 4:52pm.

- physics -
**drwls**, Wednesday, February 15, 2012 at 5:04pmThe time to reach the building, if it does not hit the ground first, is

L/(Vo*cos40) = 50/(25 cos40) = 2.61 seconds

The time to hit the ground, if it does not hit the building first, is

2 Vo sin40/g = 3.28 s

Therefore it hits the building (assuming it is tall enough so that the projectile can't go over the top).

To find out where it hits, use the

y vs t equation:

y = Vo*sin40*t - (g/2)t^2

and use t = 2.61 s

**Related Questions**

physics - a projectile is launched at a velocity of 125m/s at an angle of 20 ...

Physics - A projectile is fired from ground level with a speed of 40 m/s at an ...

physics - a projectile shot at an angle of 60 degrees above the horizontal ...

physics - a projectile is fired from the top of a building with an initial ...

PHYSICS - A Projectile IS FIRED FROM THE TOP OF A BUILDING WITH AN INITIAL ...

Science - Physics - When a projectile is fired horizontally, which of the ...

Physics - A catapult throws a projectile at a 40.0° angle with a velocity of 26....

physic - A ball is shot from the top of a building with an initial velocity of ...

Physics - A projectile is shot horizontally at 30m/s from the roof of a building...

Physics - A projectile is shot horizontally at 30m/s from the roof of a building...