Q1) For the reaction, A to B,
Delta H= +11.00 kJ mol-1 and Keq is 12.50
Calculate i) delta G and ii) delta S at 25 C (degrees celcius)
0 C degrees celcius = 273.15 K; R = 8.314 J K-1 mol-1]
To calculate delta G and delta S for the reaction A to B at 25 degrees Celsius, you can use the following equations:
i) ΔG = ΔH - TΔS
ii) ΔG = -RTln(Keq)
To calculate ΔG, we need to know ΔH, T (temperature), and ΔS.
To calculate ΔS, we can rearrange equation i) as follows:
ΔS = (ΔH - ΔG) / T
Now let's calculate the values:
Given:
ΔH = +11.00 kJ mol-1
Keq = 12.50
T = 25 degrees Celsius = 25 + 273.15 K = 298.15 K
R = 8.314 J K-1 mol-1
i) ΔG = ΔH - TΔS
ii) ΔG = -RTln(Keq)
From equation ii), we can rearrange it to solve for ΔS:
ΔS = (ΔH - ΔG) / T
Now substitute the known values into the equations:
i) ΔG = -RTln(Keq)
= -(8.314 J K-1 mol-1)(298.15 K) ln(12.50)
ii) ΔS = (ΔH - ΔG) / T
= (11.00 kJ mol-1 *1000 J / 1 kJ - (-RTln(12.50))) / 298.15 K
To calculate the values, plug these equations into a calculator to determine ΔG and ΔS.