Posted by Mom on .
When a 77 g piece of metal with a temperature of 88 Degree Celsius is placed into 277 g of water having a temperature of 20 degree Celsius, the final temperature of the metal and water is 23.3 degree Celsius. What must be the specific heat of the metal?

Chemistry 
DrBob222,
heat lost by metal + heat gained by water = 0
[mass metal x specific heat metal x (TfinalTinitial)] + [mass H2O x specific heat H2O x (TfinalTinitial)] = 0
Substitute and solve for specific heat metal. 
Chemistry 
Mom,
Thank you bob. However, what is specific heat of a metal is e metal is unknown.

Chemistry 
DrBob222,
The problem asks for the specific heat of the metal. That's what you're solving for. Substitute the numbers and solve for specific heat.
[77 x sp.h.metal x (23.320.0)] + [277 x 4.184 x (23.320.0)] = 0
You have only one unknown; i.e., specific heat metal. Solve for that.