Posted by Mom on Tuesday, February 14, 2012 at 11:07pm.
heat lost by metal + heat gained by water = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for specific heat metal.
Thank you bob. However, what is specific heat of a metal is e metal is unknown.
The problem asks for the specific heat of the metal. That's what you're solving for. Substitute the numbers and solve for specific heat.
[77 x sp.h.metal x (23.3-20.0)] + [277 x 4.184 x (23.3-20.0)] = 0
You have only one unknown; i.e., specific heat metal. Solve for that.
Related Questions
Chemistry - When a 77 g piece of metal with a temperature of 88 Degree Celsius ...
Chemistry - When a 77 g piece of metal with a temperature of 88 Degree Celsius ...
Physics 100 - A 355-g piece of metal at 48.0 degree celsius is dropped into 111g...
physics - a 200g aluminum container has 500g of water with an initial ...
physics - a 200g aluminum container has 500g of water with an initial ...
Chemistry - A 125-g piece of metal is heated to 288 degrees celsius and dropped ...
Chemistry - A sample of zinc with a mass of 14g was heated to 98 degree celsius ...
chemistry - If a hot piece of metal (at 80 degrees Celsius) is placed in cold ...
AP Chemistry - A 500 g piece of metal at 60 degrees celsius is placed in 200g of...
Chemistry - What volume of 15 degree celsius water must be added to a 1.2KG ...
For Further Reading
