Posted by **anonymous** on Tuesday, February 14, 2012 at 8:36pm.

A commuter airplane starts from an airport and takes the route shown in the figure below. The plane first flies to city A, located 175 km away in a direction 30.0° north of east. Next, it flies for 150 km 20.0° west of north, to city B. Finally, the plane flies 190 km due west, to city C. Find the location of city C relative to the location of the starting point.

distance km

angle ° west of north

- Physics -
**drwls**, Tuesday, February 14, 2012 at 9:21pm
Do a vector addition. If you don't know how, you need to study harder.

- Physics -
**SocialistHero**, Tuesday, May 14, 2013 at 12:51am
airport to A

Distance east: cos 30 = east / 175

east = 151.55 km

Distance north: sin 30 = north / 175 = 87.5 km

A to B

Distance north: cos 20 = north / 150

north = 140.95 km

Distance west: sin 20 = west / 150 = 51.3km

B to C =190km west

Distance west from airport to C=-151.55 + 51.3 + 190 = 89.75km

Distance north from airport = 87.5 + 140.95 = 228.45

Using Pythagoras theorem

h^2 = 89.75 ^ 2 + 228.95 ^ 2

h = 245.45 km

tan theta = 89.75/228.45

theta = 21.45 deg

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