Posted by **j** on Tuesday, February 14, 2012 at 4:48pm.

A golfer drives a ball with a velocity of 42 m/s at an angle of 45 degrees above the horizontal. What is the maximum height (in meters) of the ball above the level fairway?

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**bobpursley**, Tuesday, February 14, 2012 at 4:52pm
figure vertical velocity intial: 42sin45

then, knowing the vertical velocity at the peak is zero...

Vf^2=Vi^2+2gd

figure d

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**j**, Tuesday, February 14, 2012 at 4:57pm
so does that mean vf is zero, vi is 29.69848481, and g is 9.8

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**bobpursley**, Tuesday, February 14, 2012 at 5:03pm
g is -9.8m/s^2, so the answer d will be postive, or it should be. Your carrying all those digits on V is nonsense. You are restricted to two significant digits, given the info in the problem.

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