A golfer drives a ball with a velocity of 42 m/s at an angle of 45 degrees above the horizontal. What is the maximum height (in meters) of the ball above the level fairway?
physics - bobpursley, Tuesday, February 14, 2012 at 4:52pm
figure vertical velocity intial: 42sin45
then, knowing the vertical velocity at the peak is zero...
physics - j, Tuesday, February 14, 2012 at 4:57pm
so does that mean vf is zero, vi is 29.69848481, and g is 9.8
physics - bobpursley, Tuesday, February 14, 2012 at 5:03pm
g is -9.8m/s^2, so the answer d will be postive, or it should be. Your carrying all those digits on V is nonsense. You are restricted to two significant digits, given the info in the problem.