2. Solve this equation: 80 = 3y + 2y + 4 + 1.
A. y = –15
B. y = 1/5
C. y = 75
[D. y = 15]
i don't realy know if that is correct because i think it could be negative like in a please let me know
80 = 3y + 2y + 4 + 1.
80 = 5y + 5
80 - 5 = 5y
75 = 5y
75/5 = y
Yes. D is correct.
15 = y
To solve the equation 80 = 3y + 2y + 4 + 1, you need to combine like terms and isolate the variable y. Here's how you can do it step by step:
1. Combine like terms: To begin, add the coefficients of the y terms. You have 3y + 2y = 5y. The equation now becomes 80 = 5y + 4 + 1.
2. Simplify the expression: Next, simplify the right side of the equation by combining the constant terms. 4 + 1 = 5, so the equation becomes 80 = 5y + 5.
3. Isolate the variable: To isolate the variable y, subtract 5 from both sides of the equation. We have 80 - 5 = 5y + 5 - 5, which simplifies to 75 = 5y.
4. Solve for y: Finally, divide both sides of the equation by 5 to solve for y. We get 75/5 = 5y/5, which simplifies to 15 = y.
Therefore, the correct solution to the equation is y = 15.
Option D, y = 15, is the correct answer choice. It is positive, not negative.