. An IRS auditor randomly selects 3 tax returns from 59 returns of which 11 contain errors. What is the probability that she selects none of those containing errors? Round to four decimal places.
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That's what i got, hope it helped (:
To find the probability that the IRS auditor selects none of the tax returns containing errors, we need to calculate the probability of selecting a tax return without an error for each selection.
First, let's calculate the probability of selecting a tax return without an error for a single selection:
The total number of tax returns without errors is given by: total returns - returns with errors = 59 - 11 = 48.
The total number of tax returns is 59.
Therefore, the probability of selecting a tax return without an error for a single selection is: 48/59.
Since there are 3 selections, the probability of selecting none of the tax returns containing errors is calculated by multiplying the probabilities of each individual selection:
P(None of the 3 returns containing errors) = (48/59) * (47/58) * (46/57)
Calculating this expression will give you the desired probability. Rounding the result to four decimal places will provide the answer.