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April 20, 2014

April 20, 2014

Posted by **John** on Tuesday, February 14, 2012 at 1:38pm.

- Chemistry -
**DrBob222**, Tuesday, February 14, 2012 at 4:19pm20 ppm = 20 mg NaClO4/L

10 L would be 200 mg NaClO4/10 L.

I would weigh 200 mg NaClO4 and dump it into 10L water. (That isn't quite right since it is mg/L soln and not mg/L H2O so if it is done right, you would weigh 200 mg NaClO4, dissolve it in some water, then make to a final volume of 10.0L).

M = ?

20 mg/L is 0.02 g/L

0.02 g = ? mols.

0.02/molar mass NaClO4

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