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March 30, 2015

March 30, 2015

Posted by **Jake** on Tuesday, February 14, 2012 at 12:45am.

f(x) = sqrt(x+1), a=0

- Calculus -
**jack**, Wednesday, February 15, 2012 at 12:13pm1) you find y' (dy/dx) (f'(x))

2) replace each x by a which equal to one

f(x) = (x+1)^1/2

f'(x) = 1/2 (x+1)^-1/2 (1)

f'(x) = 1 / 2(x+1)

f'(0) = 1/ 2(0+1) = 1/2 = 0.5

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