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February 1, 2015

February 1, 2015

Posted by **Kristyn** on Monday, February 13, 2012 at 9:09pm.

- chemistry -
**DrBob222**, Monday, February 13, 2012 at 9:15pmp1v1 = p2v2

- chemistry -
**Kristyn**, Monday, February 13, 2012 at 9:23pmi don't understand how that is the answer. it is supposed to be a number.

- chemistry -
**DrBob222**, Monday, February 13, 2012 at 9:27pmI rarely work a problem; I try to show you HOW to do it. All you need to do is to substitute the numbers in the problem into the formula I gave you, punch in the numbers on your calculator and out comes the answer. Post your work if you get stuck.

- chemistry -
**Kristyn**, Monday, February 13, 2012 at 9:28pmWhat numbers go where though

- chemistry -
**DrBob222**, Monday, February 13, 2012 at 9:40pmThanks for telling me what difficulty you are having.

A**300 mL sample**of hydrogen gas is at a**pressure of 0.500 kPa.**If the**pressure increases to 0.750 kPa,**what will be the**final volume**of the sample? Assume that the temperature stays constant

I have highlighted what you read in the problem and how you substitute into the formula I gave you to solve the problem.

The formula I gave you is

p1v1 = p2v2

v1 = 300 mL

p1 = 0.500 kPa.

p2 = 0.750 kPa.

v2 = ?

So 0.500*300 = 0.750*v2

v2 is the unknown and that is the only unknown in the formula. Solve for v2. The answer will have units of mL. Let me know if this doesn't help but tell me what you don't understand.

- chemistry -
**Andrelle**, Friday, January 23, 2015 at 2:32pmThe answer to this problem Is 200mL.

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