Posted by **Anonymous** on Monday, February 13, 2012 at 5:58pm.

Find an equation of the line that is tangent to the graph of f and parallel to the given line.

Function

f(x) = 2x^2

Line

6x – y + 4 = 0

- MATH -
**Reiny**, Monday, February 13, 2012 at 6:07pm
f'(x) = 4x

slope of given line = 6

so

4x = 6

x = 3/2

then y = 9/2

since new line is parallel to old line, it should look like

6x- y= K

plug in point (3/2, 9/2)

6(3/2) -9/2 =k

k = 9/2

so 6x - y = 9/2, or

12 - 2y = 9

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