Posted by DCM on Monday, February 13, 2012 at 5:24pm.
I did this yesterday for someone:
Power = V i = 1300 * i = 2*10^6
so
i = (2/1.3)*10^3 = 1.54 * 10^3 amps (big current!)
R = 2 * 7 * 5 * 10^-2 = .7 Ohms
Power loss = i^2 R = (1.54)^2*10^6*.7 = 1.66*10^6 Watts (we lose about as much as we use)
-------------------
Now use a high voltage line
i = 1.54*10^3/120 = 12.8 amps (reasonable now)
power loss = i^2 R = 12.8^2 (.7) = 115 Watts, about a 100 watt light bulb worth lost now.
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